Example for Stream Density Calculations

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Density Correction for Solutions & Data Fitting

Given the following data for (NH4)2SO4 @ 20°C (Source: CRC Handbook of Chemistry and Physics, 60th Edition), data fitting gives the following:

MF Density (g/cm3)
0.005 1.003
0.01 1.0059
0.02 1.0119
0.03 1.0178
0.04 1.0238
0.05 1.0297
0.06 1.0356
0.07 1.0416
0.08 1.0475
0.09 1.0534
0.1 1.0593
0.12 1.071
0.14 1.0827
0.16 1.0943
0.18 1.1059
0.2 1.1174
0.22 1.1289
0.24 1.1403
0.26 1.1516
0.28 1.1629
0.3 1.1742
0.32 1.1854
0.34 1.1966
0.36 1.2077
0.38 1.2188
0.4 1.2298


Image:Models-Main-image059.jpg

Thus, density correction equation used in SysCAD is Poly(1, 0.5973, -0.0305, -0.1316, 0.1661). See Density Correction Function.

Density Correction for Solution with two solutes

Consider the following example at a temperature of 40°C.

Species Mass Wt%
H2O(l) 91.5
NaCl(aq) 2.4
H2SO4(aq) 6.1

From Density Correction Function we have the following equations:

  1. \mathbf{\mathit{DensCorrFn(MF)_i=a+bMF+cMF^2+dMF^3+eMF^4}}
  2. \mathbf{\mathit{MF_i=\frac{Solute_i}{Solvent+Solute_i}}}
  3. \mathbf{\mathit{Density\ Correction_i=DensCorrFn\ (MF)_i-DensCorrFn\ (0)_i}}
  4. \mathbf{\mathit{Density_{Solution}=Density_{pure\ solvent}\times\left(1.0+\sum_i^n Density\ Correction\right)}}

Basis: 1 kg of Fluid.

Density of Water:

The Density of Water varies with temperature, please see Steam / Water Properties. At 40°C Water Density = 992.216 kg/m3.

Density of H2SO4(aq)

\mathbf{\mathit{H_2SO_4\ DensCorrFn=1+0.5394x+1.4827x^2-4.6384x^3+7.2207x^4-3.7737x^5}}

Where x is the mass fraction of H2SO4(aq) in solution.
(Ref: Lide D.R. Handbook of Chemistry and Physics 74th Edition CRC Press)

Density of NaCl(aq)

\mathbf{\mathit{NaCl\ DensityCorrFn=1+0.7033x-0.6156x^2+1.1389x^3-2.2921x^4+2.2305x^5}}

Where x is the mass fraction of NaCl(aq) in solution.
(Ref: Lide D.R. Handbook of Chemistry and Physics 74th Edition CRC Press)
Note: The valid range of this equation is between 0 and 30% NaCl(aq) solutions.

Therefore, using equations 2&3:

\mathbf{\mathit{H_2SO_4(aq):\times = 0.061/(0.061+0.915) = 0.0625}} è \mathbf{\mathit{Density Correction = 0.0385.}}
\mathbf{\mathit{NaCl(aq): \times = 0.024/(0.024+0.915) = 0.0256}} è \mathbf{\mathit{Density Correction = 0.0176}}

From Equation 4

\mathbf{\mathit{Soln Density}} \mathbf{\mathit{= Density Water \ at \ 40^{\circ} C * (1 + \sum density \ correction)}}
\mathbf{\mathit{= 992.216 * ( 1 + 0.0385 + 0.0176) kg/m^3}}
\mathbf{\mathit{= 1047.92 kg/m3}}

If the user did not have the formulae for the ionic solution densities and used the densities of the pure substances, then the liquid density would be calculated as follows:

\mathbf{\mathit{H_2SO_4(aq): 1841.0 kg/m^3}}
\mathbf{\mathit{NaCl(aq): 2165.0 kg/m^3}}
\mathbf{\mathit{Water density \ at \ 40^{\circ}C \ is \ 992.216 kg/m^3}}

Using Equation described in Example 1,

\mathbf{\mathit{Liquid Density}} \mathbf{\mathit{= 1/((0.915 / 992.216) + (0.061 / 1841) + (0.024 / 2165))}}
\mathbf{\mathit{= 1034.77 kg/m3}}

This gives an error of ~1%.

Density and Volume display for mixtures:

Consider the following example at 40 °C & atmospheric pressure; determine the volumetric flow of the stream.

Basis: 1000 kg/h

Component

Mass Fraction

Density

(kg/m3)

Density Correction

Individual Volume Display (m3/h)

NaCl(aq)

0.0900

*

As per example 3

*

H2SO4(aq)

0.0900

*

As per example 3

*

H20

0.6300

992.216

As per example 3

0.6349

CuO(s)

0.0550

6450

-

0.0085

Cu(s)

0.0450

8920

-

0.0050

MgCO3(aq)

0.0450

1000

-

0.045

CuSO4(aq)

0.0450

1000

-

0.045


To determine the stream volumetric flow of the stream, we need to first compute the corrected solution density the mixture of Water-NaCl-H2SO4. See Example 3 above for equations.

Component

Mass flow

(kg/h)

MFi

(Equation 2)

Correction Factor

(Equation 3)

NaCl(aq)

90

0.125

0.0800

H2SO4(aq)

90

0.125

0.0832

H20

630

 

 


So using Equation 4 (see Example 3)

\mathbf{\mathit{Density \ solution}} \mathbf{\mathit{= Density_{ Water \ at \  40^{\circ}\ C} * (1 + \sum density \ correction)}}
\mathbf{\mathit{= 992.216 * (1 + 0.08 + 0.0832) = 1154.15 kg/m^3}}


\mathbf{\mathit{Liquid \ Density}} \mathbf{\mathit{= (90+90+630+45+45) / [ (90+90+630)/1154.15 + 45/1000 + 45/1000 ]}}
\mathbf{\mathit{= 1136.63 kg/m^3}}
\mathbf{\mathit{Liquid \ Vol \ Flow}} \mathbf{\mathit{= 900/1136.63 = 0.7918 m^3/h}}


\mathbf{\mathit{Solids \ Density}} \mathbf{\mathit{= 100 / (55/6450 + 45/8920) = 7368.12 kg/m^3}}
\mathbf{\mathit{Solids \ Vol \ Flow}} \mathbf{\mathit{= 100/7368.12 = 0.01357 m^3/h}}


\mathbf{\mathit{Stream \ Volume}} \mathbf{\mathit{= 0.7918 + 0.01357 = 0.80537 m^3}}
\mathbf{\mathit{Stream \ Density}} \mathbf{\mathit{= 1000 / 0.80537 = 1241.67 kg/m^3}}
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